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Question

1+cos A1cos A = ?

(a) cosec A - cot A (b) cosec A + cot A

(c) cosec A cot A (d) none of these

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Solution


LHS- 1+cos A1cos A

Multiplying with 1+cos A on both numerator and denominator, we have,

=1+cos A1cos A×1+cos A1+cos A

=(1+cos A)21cos2 A

=1+cos Asin2 A
=1+cos Asin A

=1sin A+cos Asin A

=cosecA + cotA

(b)


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