Question

$\sqrt{V}$ on two particles A and B are plotted against de-broglie wavelengths. Where V is the potential on the particles . Which of the following relation is correct about the mass of particles?

• A. $m_A=m_B$
• B. $m_A>m_B$
• C. $m_A<m_B$
• D. $m_A\le m_B$

Answer 1

The correct option is B $m_A>m_B$

Charge q is the same but masses of both the particles are different $(m_A>m_B)$

The de Broglie wavelength is given by

$\lambda =h/(2mqV{)}^{-1/2}$

The slope of the smaller mass is larger, therefore plot A in the above graph is for mass m2