Square matrix - a ij - n - n will be an upper triangular matrix- ifA- None of these B- a i j -0- for i - jC- a ij -0- for i - jD- ai j-0- for i-j

The correct option is C a_ij= 0, for i gt;j [a_ij]_n× n square matrix is a upper triangular matrix for a_ij= 0, for i gt;j. ...

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Triangular Matrix

Square matrix...

Question

Square matrix $[a_{i j}]_{n \times n}$ will be an upper triangular matrix, if

$a_{i j} \neq 0$ , for i>j

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$a_{i j} = 0$ , for i>j

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$a_{i j} = 0$ , for i<j

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$N o n e o f t h e s e$

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Solution

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Similar questions

[a_{i j}]_{n \times n}

[a_{i j}]_{n \times n}

A = {[a_{i j}]}_{n \times n}

a_{i j} = 0

A = [a_{i j}]_{n \times n}

a_{i j} = 0

i > j,

(a_{i j})

a_{i j} = 0

i \neq j

a_{i j} = k

i = j

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