Question

Question 12

Square of $\left(\frac{-2}{3}\right)$ is
(a)$\frac{-2}{3}$
(b)$\frac{2}{3}$
(c)$\frac{-4}{9}$
(d)$\frac{4}{9}$

Answer 1

Square of $\left(\frac{-2}{3}\right)$ is ${\left(\frac{-2}{3}\right)}^2$.
So, ${\left(\frac{-2}{3}\right)}^2=\left(\frac{-2}{3}\right)\times \left(\frac{-2}{3}\right)=\frac{4}{9}$[$\because$ muliplication of two rational numbers with same sign is always positive.]