''Square of the sum of two number is equal to the sum of the squares of the number and twice the product of the numbers ,'' Write suitable equation to the data

(a + b)^{2} = a^{2} + 2 a b

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(a + b)^{2} = a^{2} + b^{2} + 2 a b

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(a + b)^{2} = a^{2} + b^{2}

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(a + b)^{2} = a^{2} + b^{2} - 2 a b

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Solution

The correct option is A $(a + b)^{2} = a^{2} + b^{2} + 2 a b$
$(a + b)^{2} = a^{2} + b^{2} + 2 a b$

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Similar questions

Which of the following is correct?
a) $(a - b)^{2} = a^{2} + 2 a b - b^{2}$
b) $(a - b)^{2} = a^{2} - 2 a b + b^{2}$
c) $(a - b)^{2} = a^{2} - b^{2}$
d) $(a + b)^{2} = a^{2} + 2 a b - b^{2}$

Q. Question 3

Which of the following is correct?
a)

(a - b)^{2} = a^{2} + 2 a b - b^{2}

(a - b)^{2} = a^{2} - 2 a b + b^{2}

(a - b)^{2} = a^{2} - b^{2}

(a + b)^{2} = a^{2} + 2 a b - b^{2}

Find the square of the following numbers using the formula:

(a − b)² = a² − 2ab + b²

Find the squares of the following numbers using the formula.

(a + b)² = a² + 2ab + b²

Q. If A and B are square matrices of the same order, explain, why in general
(i) (A + B)² ≠ A² + 2AB + B²
(ii) (A − B)² ≠ A² − 2AB + B²
(iii) (A + B) (A − B) ≠ A² − B².

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''Square of the sum of two number is equal to the sum of the squares of the number and twice the product of the numbers ,'' Write suitable equation to the data

The correct option is A (a+b)2=a2+b2+2ab(a+b)2=a2+b2+2ab

The correct option is A $(a + b)^{2} = a^{2} + b^{2} + 2 a b$
$(a + b)^{2} = a^{2} + b^{2} + 2 a b$