Question

square root of 72+ square root of 800- square root of root 18 (SIMPLIFY)

Answer 1

Dear Student,

$$\begin{gathered} \sqrt{72}+\sqrt{800}-\sqrt{18} \\ =\sqrt{2\times 2\times 2\times 3\times 3}+\sqrt{2\times 2\times 2\times 2\times 2\times 5\times 5}-\sqrt{2\times 3\times 3} \\ =2\times 3\sqrt{2}+2\times 2\times 5\sqrt{2}-3\sqrt{2} \\ =6\sqrt{2}+20\sqrt{2}-3\sqrt{2} \\ =\sqrt{2}(6+20-3) \\ =\sqrt{2}\left(23\right) \\ =23\sqrt{2} \\ \mathrm{therefore}\sqrt{72}+\sqrt{800}-\sqrt{18}=23\sqrt{2}. \end{gathered}$$

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