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Question

Square root of the poynomial is (3x+2y)224xy

A
(3x2y)
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B
(3x+2y)
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C
(2x3y)
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D
(2x+3y)
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Solution

The correct option is A (3x2y)
(3x+2y)224xy
=9x2+4y2+12xy24xy
=9x2+4y212xy
=(3x2y)2
=(3x2y)

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