Squares of which of the following numbers will have 1 (one) at their unit's place:

(i) 57 (ii) 81

(iii) 139 (iv) 73

(v) 64

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Solution

The squares of the following numbers will have 1 at their units place as $(1)^{2} = 1, (9)^{2} = 81$

81 and 139 i.e., (ii) and (iii)

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Square of which of the following numbers will not have 6 at their unit's place :

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(iii) $(69^{2}$ (iv) $(321^{2}$

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