Stability of hydrides of carbon family is in order :

C H_{4} > S i H_{4} > G e H_{4} > S n H_{4} > P b H_{4}

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C H_{4} < S i H_{4} < G e H_{4} < S n H_{4} < P b H_{4}

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C H_{4} > S n H_{4} > G e H_{4} > S i H_{4} > P b H_{4}

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None of these

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Solution

The correct option is A $C H_{4} > S i H_{4} > G e H_{4} > S n H_{4} > P b H_{4}$
Hydrides of carbon are more stable since elelctronegativity values of carbon and hydrogen are nearly same.

Hydride of carbon family is stable when carbon is near to nucleus, thus its attraction is more towards valence shell electrons, so it is more stable.

Hydrides of silicon are less stable because in silanes hydrogen withdraw electrons from Si-H bond.
As we move down, electronegativity decreases so stability decreases.

$C H_{4} > S i H_{4} > G e H_{4} > S n H_{4} > P b H_{4}$ is correct order.

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