The correct option is D KOH in C2 H5 OH (c) R CH_2 CCl_2 R R C≡ C R This reaction is an example of dehydrohalogenation. Hence, alcoholic KOH is used as a ...

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Standard XII

Chemistry

Dehydrohalogenation of Dihalides

Reagent is:

Question

Reagent is:

$ \stackrel{\text { Reagent }}{\longrightarrow} $ $ R-C \equiv C-R $

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HCl and H₂O

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KOH in C₂ H₅ OH

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Solution

The correct option is C
KOH in C₂ H₅ OH

(c) $R - C H_{2} - C C l_{2} - R K O H + C_{2} H_{5} O H - ---------- \to R - C \equiv C - R$

This reaction is an example of dehydrohalogenation.

Hence, alcoholic KOH is used as a reagent.

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Similar questions

Complete and balance the following reactions.

(a) $N a + H_{2} O \to$ _________ + _________

(b) $C a + H_{2} O \to$ __________+_________

(d) $Z n + H_{2} O \to$ ___________+_________

(e) $F e + H_{2} O \to$ ____________+_________

(f) $Z n + H C l \to$ _____________+__________

(g) $A l + H_{2} S O_{4} \to$ __________+_________

(h) $F e + H C l \to$ ___________+____________

(i) $Z n + N a O H \to$ __________+____________

(j) $A l + K O H + H_{2} O$ _________+____________

Q. Predict

R_{1}

, A and

R_{2}

respectively in the given reaction:

C H_{3} - C H_{2} - C l R_{1} - \to A R_{2} - \to C H_{3} - C H_{3}

Q. Which choice or choices demonstrate amphoterism?
i.

H C l + H_{2} O \to H_{3} O^{+} + C l^{-}

and

H_{2} O + N_{3} \to O H^{-} + N H_{4}^{-}

ii.

H S^{-} + H C l \to C l^{-} + H_{2} S

and

H S^{-} + N H_{3} \to N H_{4}^{+} + S^{2 -}

iii.

H C l + N a O H \to N a C l + H_{2} O

and

N a C l + H_{2} O \to H C l + N a O H

Q. The reagent used in the following reaction is .

R - C H_{2} - C C l_{2} - R ⟶ R - C H = C C l - R

Q. Which of the following reaction(s) yields

H_{2}

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Reagent is: \( \stackrel{\text { Reagent }}{\longrightarrow} \) \( R-C \equiv C-R \)

The correct option is C KOH in C2 H5 OH (c) R−CH2−CCl2−RKOH + C2H5OH−−−−−−−−−−−→R−C≡C−R This reaction is an example of dehydrohalogenation. Hence, alcoholic KOH is used as a reagent.

Reagent is:

\( \stackrel{\text { Reagent }}{\longrightarrow} \) \( R-C \equiv C-R \)

The correct option is C
KOH in C₂ H₅ OH

(c) $R - C H_{2} - C C l_{2} - R K O H + C_{2} H_{5} O H - ---------- \to R - C \equiv C - R$

This reaction is an example of dehydrohalogenation.

Hence, alcoholic KOH is used as a reagent.