Standard conditions using a Kelvin thermometer are :

760 torr, 273 K

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760 torr, 273 K, 1 L

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760 torr, 0 K

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0 torr, 0 K

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0 torr, 273 K, 1 L

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Solution

The correct option is E 760 torr, 273 K
Standard condition temperature $=$ $0^{0} C$ $=$ $273 K$
Standard condition pressure $=$ $1 a t m$ $=$ $760 t o r r$

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Similar questions

1.8 {g L}^{- 1}

760 torr

27^{\circ} C

(G i v e n R = 0.082 L atm K^{- 1} {mol}^{- 1}, 760 torr = 1 atm, 0^{\circ} C = 273 K)

273 K

1.8 g L^{- 1}

760 t o r r

27^{\circ} C

(G i v e n R = 0.082 L a t m K^{- 1} m o l^{- 1}, 760 t o r r = 1 b a r, 1^{o} C = 273 K)

The unit torr is related to the barometric height as

(a) 1 torr = 1 cm of Hg

(b) 1 torr = 0.76 m of Hg
(c) 1 torr = 1 mm of Hg

(d) 1 torr = 1 m of Hg

(P_{A}^{0} = 150 t o r r)

(P_{B}^{0} = 240 t o r r)

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