Question

Standard deviation for $x_1,x_2,.....x_n$ about mean can be expressed as $\sqrt{\frac{1}{n}{\sum }_{i=1}^n(x_i-\overline{x}{)}^2}$.

• A. True
• B. False

Answer 1

The correct option is A

True

We know variance also expressed as ${\sigma }^2=\frac{1}{n}{\sum }_{i=1}^n(x_i-\overline{x}{)}^2$ we call standard deviation as the square roof of variance $\left({\sigma }^2\right)$. Therefore $\sigma =\sqrt{\frac{1}{n}{\sum }_{i=1}^n(x_i-\overline{x}{)}^2}$.