Standard deviation of two distribution are same and their arithmetic means are 30 and 25 respectively. If their coefficient of variation is $v_{1}$ and $v_{2}$ , then $6 v_{1} - {5 v}_{2}$ is equal to ___________________.

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Solution

Given: Standard deviation of two distributions are same and their arithmetic mean are $30$ and $25$ and their coefficient variance are $v_{1}$ and $v_{2}$

$∵ (S D)_{1} = (S D)_{2} = (S D)$ (given)

Coefficient of variation $C V = \frac{S D}{m e a n}$

$\Rightarrow v_{1} = \frac{S D}{30}$ and $v_{2} = \frac{S D}{25}$

$∴ 6 v_{1} - 5 v_{2} = 6 \times \frac{S D}{30} - 5 \times \frac{S D}{25}$

$\Rightarrow 6 v_{1} - 5 v_{2} = \frac{S D}{5} - \frac{S D}{5}$

$\Rightarrow 6 v_{1} - 5 v_{1} = 0$

$∴ 6 v_{1} - 5 v_{1} = 0$ is correct answer.

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Standard deviation of two distribution are same and their arithmetic means are 30 and 25 respectively. If their coefficient of variation is v1 andv2, then 6v1−5v2 is equal to ___________________.

Standard deviation of two distribution are same and their arithmetic means are 30 and 25 respectively. If their coefficient of variation is $v_{1}$ and $v_{2}$ , then $6 v_{1} - {5 v}_{2}$ is equal to ___________________.