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Electrode Potential

Standard elec...

Question

Standard electrode potential:
$F e^{2 +} + 2 e^{-} \to F e; E^{0} = - 0.44 V$
$F e^{3 +} + e^{-} \to F e^{2 +}; E^{0} = 0.77 V$

When an iron electrode is dipped in $F e^{2 +} and F e^{3 +}$ aqueous solution to form a half cell, then

A

F e^{2 +}

concentration will increases in solution

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B

F e^{3 +}

concentration will decreases in solution

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C

F e^{2 +} and F e^{3 +}

concentration reamins unchanged in solution

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D

F e^{2 +}

concentration will decreases in solution

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Solution

The correct option is B $F e^{3 +}$ concentration will decreases in solution
Standard reduction potential of $F e^{2 +} / F e$ is less than $F e^{3 +} / F e^{2 +}$ couple.
Hence, $F e$ will get oxidised to $F e^{2 +}$ ions and $F e^{3 +}$ ions will get reduced to $F e^{2 +}$ .
Hence, both reaction will result in increase of $F e^{2 +}$ concentration in the solution.
Since, $F e^{3 +}$ is getting reduced to $F e^{2 +}$ ions, $F e^{3 +}$ concentration will decrease in the solution.

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Similar questions

Given standard electrode potentials:

$F e^{3 +} + 3 e^{-} \to F e; E^{0} = - 0.036 V$

$F e^{2 +} + 2 e^{-} \to F e; E^{0} = - 0.440 V$

The standard electrode potential $E^{o}$ for $F e^{3 +} + e^{-} \to F e^{2 +}$ is:

Q. Given standard electrode potential

F e^{2 +} + 2 e^{-} \to F e; E^{0} = - 0.440 V

F e^{3 +} + 3 e^{-} \to F e; E^{0} = - 0.036

V. Calculate the electrode potential of cell.

Q. Standard electrode potentials of

F e^{2 +} + 2 e \to F e

F e^{3 +} + 3 e \to F e

- 0.440

- 0.036

V respectively. The standard electrode potential

(E^{0})

F e^{3 +} + e \to F e^{2 +}

Q. Standard electrode potentials of

F e^{2 +} + 2 e^{-} \to F e

F e^{3 +} + 3 e^{-} \to F e

- 0.440 V

- 0.036 V

respectively.
The standard electrode potential (

E^{0}

F e^{3 +} + e^{-} \to F e^{2 +}

Q. Standard electrode potentials of

F e^{2 +} + 2 e^{-} \to F e

F e^{3 +} + 3 e^{-} \to F e

- 0.440 V

- 0.036 V

respectively.
The standard electrode potential (

E^{0}

F e^{3 +} + e^{-} \to F e^{2 +}

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