Standard entropy of X2-Y2 and XY3 are 60-40 and 50 JK-1 mol-1- respectively- For the reaction- 12X2-32Y2-XY3- H-30kJ to be at equilirbium- the temperature will be-

Standard entropy of $X_{2}$ , $Y_{2}$ and $X Y_{3}$ are 60, 40 and 50 $J K^{- 1} m o l^{- 1}$ respectively. For the reaction: $\frac{1}{2} X_{2} + \frac{3}{2} Y_{2} \to X Y_{3}, Δ H = - 30 k J$ to be at equilibrium, the temperature will be :

Q. Standard entropy of

X_{2}, Y_{2}

and

X Y_{3}

are

60, 40

and

50 J K^{- 1}

{m o l}^{- 1}

, respectively for the reaction,

\frac{1}{2} X_{2} + \frac{3}{2} Y_{2} ⟶ X Y_{3}, △ H = - 30 k J

, to be at equilibrium, the temperature will be:

Q. Standard entropy of

X_{2}

Y_{2}

and

X Y_{3}

are 60, 40 and

50 J K^{- 1} m o l^{- 1}

respectively. For the reaction

\frac{1}{2} X_{2} + \frac{3}{2} Y_{2} \to X Y_{3}; Δ H = - 30 k J / m o l

to be at equilibrium, the temperature will be:

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Standard entropy of X2,Y2 and XY3 are 60,40 and 50 JK−1 mol−1, respectively. For the reaction,12X2+32Y2→XY3.ΔH=−30kJ to be at equilirbium, the temperature will be:

Standard entropy of $X_{2}, Y_{2}$ and $X Y_{3}$ are $60, 40$ and $50$ $J K^{- 1}$ ${m o l}^{- 1}$ , respectively. For the reaction,
$\frac{1}{2} X_{2} + \frac{3}{2} Y_{2} \to {X Y}_{3} . Δ H = - 30 k J$ to be at equilirbium, the temperature will be: