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Question

Standard free energies of formation (in kJ/mol) at 298 K are -237.2, -394.4 and -8.2 for H2O(l),CO2(g) and pentane (g), respectively. The value of E0cell for the pentane-oxygen fuel cell is:

A
1.0968V
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B
0.0968V
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C
1.968V
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D
2.0968V
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Solution

The correct option is A 1.0968V
C5H12+8O25CO2+6H2O

ΔG=G(products)G(reactants)=5×(394.4)+6×(237.2)(8.2)=3387Kjmol1

To get Ecell use the equation:

ΔG=nFEcell

As O is moving from 0 to -2 oxidation state, n = 32 for this reaction

3387×1000=32×96500×Ecell

Ecell=1.0968V

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