Question

Standard gibbs free energy change $\Delta G^o$ for a reaction is zero. The value of the equilibrium constant of the reaction will be:

Answer 1

For a reaction, $\Delta G=\Delta G^{\circ }+RT㏑K$

$\therefore$ As $\Delta G^{\circ }=0$

$\Delta G=RT㏑K$

But for equilibrium reaction, $\Delta G=0$

$\therefore RT㏑K_{eq}=0$

$\therefore K_{eq}=1$

Therefore, the value of equilibrium constant of the reaction is 1.