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Question

Standard reduction potentials of the half reactions are given below :
F2(g)+2e2F(aq); E=+2.85V
Cl2(g)+2e2Cl(aq);E=+1.36V
Br2(l)+2e2Br(aq);E=+1.06V
I2(s)+2e2I(aq);E=+0.53V
The strongest oxidising and reducing agents respectively are :

A
F2 and I
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B
Cl2 and I2
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C
Br2 and Cl
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D
Cl2 and Br
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Solution

The correct option is A F2 and I
Higher the value of reduction potential higher will be the oxidising power whereas lower the value of reduction potential higher will be the reducing power.
Because of high standard reduction potential of F2, it reduces to F. So it oxidises other elements strongly. So, it is the strongest oxidising agent. I2 has the lowest standard reduction potential here. Hence I oxidises itself strongly and reduces others. So, it is a strong reducing agent.

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