Standing waves of frequency 5.0 kHz are produced in a tube filled with oxygen at 300 K. The separation between the consecutive modes is 3.3 cm. Calculate the specific heat capacities Cp and Cv of the gas
F = 5×103Hz,
T=300K,12=3.3cm
∴l=6.6×10−2m
V=ft=5×103×6.6×10−2
= (66×5)=330m/s
v = √γRTM or V2=γRTM
∴γ=330×330×328.3×300×100=1.3995
Cv=Rγ−1=8.30.3995
= 20.7 J mol-K
Cp=Cv+R
= 20.7 J + 8.3
= 29.07 J/mol-K