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Standard XII

Chemistry

Higher Alkynes from Alkynes

Starting from...

Question

Starting from acetylene and any alkyl halide, which of the following yields cyclodecyne?

1 eq.

N a N H_{2}

and

B r (C H_{2})_{9} B r

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2 eq.

N a N H_{2}

and

B r (C H_{2})_{8} B r

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1 eq.

N a N H_{2}

and

B r (C H_{2})_{8} B r

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Both b and c

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Solution

The correct option is B 2 eq. $N a N H_{2}$ and $B r (C H_{2})_{8} B r$

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Similar questions

Q. Starting from acetylene and any alkyl halide, which of the following yields cyclodecyne?

Synthesise the given compound using the acetylene and any alkyl halide as starting material.

I n o r d e r t o c o m p l e t e t h e r e a c t i o n

1 - P e n t y n e a \to 4 - O c t a n e b \to c i s - 4 - O c t a n e a a n d b w i l l b e

(1) N a N H_{2}; a C H_{3} C H_{2} B r : H_{2} b (o n e m o l e) P d o r N i

(2) N a N H_{2}; C H_{3} C H_{2} C H_{2} B r : H_{2} (t w o m o l e s) P d o r N i

(3) N a N H_{2}; C H_{3} C H_{2} C H_{2} B r : H_{2}, (o n e - m o l e) P d o r N i

(4) N a N H_{2}; C H_{3} C H_{2} C H_{2} B r : B H_{3}, H_{2} O_{2}, O H^{-}

Suggest synthesise for :

N a N H_{2}, N_{2}

and

K N O_{3}

There are two scenarios and in either case, we start with 5-oxohexanal. A reagent or sequence of reactions "A"
helps convert the substrate into 6-hydroxyhexan-2-one. On the other hand, a reagent or sequence of reactions "B"
converts the starting compound into 5-hydroxyhexanal. A and B are:

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Starting from acetylene and any alkyl halide, which of the following yields cyclodecyne?

The correct option is B 2 eq. NaNH2 and Br(CH2)8Br

The correct option is B 2 eq. $N a N H_{2}$ and $B r (C H_{2})_{8} B r$