Question

Starting from rest, a particle moves along a circular path of radius 1 m so that the distance travelled is given by the expression $s=2t^2+c$ where c is a constant. The tangential acceleration of the particle (in m/s${}^2$) is

• A. 2
• B. 4
• C. 6
• D. 8

Answer 1

The correct option is B 4

The velocity of the particle,
$v=\frac{ds}{dt}=4t$

$\therefore$ The tangential acceleration,
$a_t=\frac{dv}{dt}=4$