Question

Starting from rest a particle moves in a straight line with acceleration
$a=[2+|t-2|]m/s^2$
What will be the velocity(in $m/s$) of particle at the end of $4s$?

Answer 1

$a=[2+|t-2|]m/s^2$

For $0<t\le 1a=3$

For

$1<t\le 2a=2$

For

$2<t<3a=2$

and

For $3\le t<4a=3$

Velocity at end of 4 sec is $=$ enclosed by the graph

$V=A=3\times 2+2\times 2=10m/s^2$