Starting from rest the fly wheel of a motor attains an angular velocity of $60 r a d / s$ in $5 s$ , the angular acceleration of the fly wheel is:

6 r a d / s^{2}

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12 r a d / s^{2}

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300 r a d / s^{2}

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150 r a d / s^{2}

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Solution

The correct option is B $12 r a d / s^{2}$
Given, $ω_{0} = 0$ , $ω = 60 r a d / s$ , $t = 5 s$

Using the equations of motion,

$ω = ω_{0} + α t$

or, $60 = 0 + α 5$

or, $α = 12 r a d / s^{2}$

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Starting from rest the fly wheel of a motor attains an angular velocity of 60rad/s in 5 s, the angular acceleration of the fly wheel is:

The correct option is B 12 rad/s2Given, ω0=0, ω=60 rad/s, t=5 sUsing the equations of motion,ω=ω0+αtor, 60=0+α5or, α=12 rad/s2

Starting from rest the fly wheel of a motor attains an angular velocity of $60 r a d / s$ in $5 s$ , the angular acceleration of the fly wheel is:

The correct option is B $12 r a d / s^{2}$
Given, $ω_{0} = 0$ , $ω = 60 r a d / s$ , $t = 5 s$

Using the equations of motion,

$ω = ω_{0} + α t$

or, $60 = 0 + α 5$

or, $α = 12 r a d / s^{2}$