CameraIcon

SearchIcon

MyQuestionIcon

1

You visited us 1 times! Enjoying our articles? Unlock Full Access!

Uniform and Non-Uniform Motion

Starting from...

Question

Starting from the extreme position, the time taken by an ideal simple pendulum to travel a distance of half the amplitude is

Open in App

Solution

The quantity $\phi = wt+\delta$ is called the phase . It determines the status of the particle in simple harmonic motion
$x= A\sin \left ( wt +\delta \right )\rightarrow$ phase
$x=\cos \omega t = \frac{A}{2}=A\cos \omega t$
$\frac{1}{2} = \cos \omega t = \omega t = \frac{\pi }{3}$
$\frac{2\pi }{T} t = \frac{\pi }{3} = t = T/6$

Suggest Corrections

thumbs-up

0

Similar questions

Q. A simple harmonic oscillator starts from extreme position and covers a displacement half of its amplitude in a time '

t

', the further time taken by it to reach mean position is

Q. The amplitude of a pendulum is
(a) the time taken for one complete oscillation.
(b) the time taken for half an oscillation.
(c) the distance between the mean position and one extreme position.
(d) the distance between one extreme position and the other extreme position.

Q. A particle executing simple harmonic motion has a period of

6 s

. The time taken by the particle to move from the mean position to half the amplitude, starting from the mean position is

Q. A particle executes simple harmonic oscillation with an amplitude

A

. If the time period of oscillation is

T

, then minimum time taken by the particle to travel half of the amplitude from the mean position is

Q. A particle executes simple harmonic oscillation with an amplitude

a

. The period of oscillation is T. The minimum time taken by the particle to travel half of the amplitude from the equilibrium position is

View More

Join BYJU'S Learning Program

similar_icon

Related Videos

lock

Time and Speed

PHYSICS

Watch in App

explore_more_icon

Explore more

Uniform and Non-Uniform Motion

Standard VII Physics

Join BYJU'S Learning Program

CrossIcon