Question

Starting with 1 mole of a compound A, it is found that the reaction is $\frac{3}{4}$ completed in 1 hour. Find the rate constant (in $M^{-1}$ $h{r}^{-1}$)if the reaction is of $2^{nd}$ order.

Answer 1

t = 1 hour

for II order

$kt=\frac{1}{a}-\frac{1}{a_0}$
$a=a_0/4$

$kt=\frac{4}{a_0}-\frac{1}{a_0}$
t = 1, $a_0=1$
$k=3$