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Question

Starting with one mole of O2 and two moles of SO2, the equilibrium for the formation of SO3 was established at a certain temperature. If V is the volume of the vessel and 2x is the number of moles of SO3 present, the equilibrium constant will be:

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Solution

2SO2(g)+O2(g)2SO3(g)
At t=0: 1V 2V 0
At equilibrium:- (1V2x) (2Vx) 2x
Now, KC=2x(1V2x)(2Vx)=2x(12xV)(2xV)
Therefore, the equilibrium constant will be 2x(12xV)(2xV).

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