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Work Done

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Question

Starting with the same initial conditions, an ideal gas expands from volume $V_{1}$ to $V_{2}$ in three different ways. The work done by the gas is $W_{1}$ if the process is purely isothermal, $W_{2}$ if purely isobaric and $W_{3}$ if purely adiabatic. Then

W_{2} > W_{1} > W_{3}

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W_{2} > W_{3} > W_{1}

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W_{1} > W_{2} > W_{3}

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W_{1} > W_{3} > W_{2}

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Solution

The correct option is A $W_{2} > W_{1} > W_{3}$
Explanation :
Curve 1 - isobaric process
Curve 2 - isothermal process
Curve 3 - idiabatic process
Since work done Area under PV graph
= $W_{2} > W_{1} > W_{3}$

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