Starting with the same initial conditions if an ideal gas expands from volume V1toV2 in three different ways. The work done by the gas is W1 in the process is purely isothermal,W2 is purely isobaric and W3 is purely adiabatic, then
A
W2>W1>W3
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B
W2>W3>W1
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C
W1>W2>W3
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D
W1>W3>W2
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Solution
The correct option is AW2>W1>W3 Area under PV graph = work done Here are A2 > Area A1 > Area A3