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Identification of Different Process

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Question

Starting with the same initial conditions, one mole of an ideal monoatomic gas expands reversibly from volume $V_{1}$ to $V_{2}$ in two different ways. The work done by gas is $w_{1}$ , if the process is purely isothermal, $w_{2}$ if purely isobaric and $w_{3}$ if purely adiabatic, then:

w_{2} > w_{1} > w_{3}

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w_{2} > w_{3} > w_{1}

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w_{1} > w_{2} > w_{3}

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w_{1} > w_{3} > w_{2}

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Solution

The correct option is A $w_{2} > w_{1} > w_{3}$
W $= - \int P d V$
It is the area under p-V diagram

From the above image, we can say that the area under the P-V curve is in the increasing order: adiabatic, isothermal and isobaric

Hence, $w_{2} > w_{1} > w_{3}$

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