Question

State and explain coulomb's inverse square law

Answer 1

Coulomb's low of inverse square states that force between two charges proportionally depend on the product of magnitude of charges and inversely dependent on the square of distance between those charges.

i.e. $F\alpha q_1{q}_2\&F\alpha \frac{1}{r^2}$

$\Rightarrow F\alpha \frac{q_1{q}_2}{r^2}$

Substituting constant,

$\overrightarrow{F}=\frac{K{q}_1{q}_2}{r^2}$

Now, Significance :- Product at both the charges implies that the force is dependent on both of charges not only one charge.

Also, $r^2$ signifies about symmetry,i.e. in any direction, for ex . $x=+S$ & $x=-S$ will have some force. which is called Symmetry.