Basic Proportionality Theorem states that, if a line is parallel to a side of a triangle which intersects the other sides into two distinct points,then the line divides those sides of the triangle in proportion.
Let ABC be the triangle.
The line l parallel to BC intersect AB at D and AC at E.
To prove ADDB=AEEC
Join BE,CD
Draw EF⊥AB, DG⊥CA
Since EF⊥AB,
EF is the height of triangles ADE and DBE
Area of △ADE=12× base × height=12AD×EF
Area of △DBE=12×DB×EF
areaofΔADEareaofΔDBE=12×AD×EF12×DB×EF=ADDB ........(1)
Similarly,
areaofΔADEareaofΔDCE=12×AE×DG12×EC×DG=AEEC ......(2)
But ΔDBE and ΔDCE are the same base DE and between the same parallel straight line BC and DE.
Area of ΔDBE= area of ΔDCE ....(3)
From (1), (2) and (3), we have
ADDB=AEEC
Hence proved.
![631188_605043_ans_86bdeb7b2b9e44bebdbad9319f8f5241.png](https://search-static.byjusweb.com/question-images/toppr_ext/questions/631188_605043_ans_86bdeb7b2b9e44bebdbad9319f8f5241.png)