State as oxidation or reduction in the given reaction: $F e^{3 +} + e^{-} \to F e^{2 +}$

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Solution

Oxidation is the loss of electrons or an increase in oxidation state by a molecule, atom, or ion. Reduction is the gain of electrons or a decrease in oxidation state by a molecule, atom, or ion.
Here, ferric ion is getting one electron and forms ferrus ion so its a reduction process.

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Identify the following reactions as either oxidation or reduction :

(i) $O + 2 e^{-} \to O^{2 -}$ (ii) $K - e^{-} \to K^{+}$ (iii) $F e^{3 +} + e^{-} \to F e^{2 +}$

N a - e^{-} \to N a^{+}

Identify the following reactions as oxidation or reduction reaction:
i) $K - e^{-} \to K^{+}$
ii) $F e^{3 +} + e^{-} \to F e^{2 +}$

O + 2 e^{-} \to O^{2 -}

F e^{2 +} \to F e^{3 +} + e^{-}

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