Question

State Brewster's law.
Find Brewster's angle for a transparent liquid having refractive index $1.5$.

Answer 1

Brewster's law says that maximum polarization will happen when the angle between the reflected ray and refracted ray is ${90}^{\circ }$.

Brewster angle ${\theta }_B=\arctan \left(\frac{n_2}{n_1}\right)$

$\Rightarrow {\theta }_B=\arctan \left(\frac{1.5}{1}\right)={56.31}^{\circ }$