Question

State factors responsible for strength of magnetic fields in a circular current carrying conductor?

Answer 1

1. We know the formula of magnetic fields at the center of a circular loop is

$$\begin{gathered} B=\frac{{\mu }_{\circ }ni}{2a} \\ Where \\ {\mu }_{\circ }=permeabilitycons\tan t \\ =4\mathrm{\pi }\times {10}^{-7}Tm{A}^{-1} \\ \mathrm{n}=\mathrm{number}\mathrm{of}\mathrm{turns} \\ \mathrm{i}=\mathrm{current}\mathrm{in}\mathrm{the}\mathrm{coil}. \\ \mathrm{a}=\mathrm{Radius}\mathrm{of}\mathrm{circular}\mathrm{loop}. \end{gathered}$$

The strength of magnetic fields at the center of the circular current-carrying conductor depends on the following factors:-

1. Current in the loop:- Strength of the magnetic field is directly proportional to the current in the circular current-carrying conductor $B\propto i$

2. Number of turns:- Strength of the magnetic field is proportional to the number of turns in the circular current-carrying conductor. $B\propto n$

3. Radius of the circular loop:- Strength of magnetic fields is inversely proportional to the radius of circular current-carrying conductor. $B\propto \frac{1}{a}$