State in brief, the meaning of each of the following:
(i) The specific latent heat of fusion of ice is $336000 J . {kg}^{- 1}$
(ii) The specific heat capacity of copper is $0.4 J . g^{- 1} {}^{\circ}C^{- 1}$

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Solution

The explanation for case(i)
The amount of heat gained by a solid object to convert it into a liquid without any further increase in the temperature is known as latent heat of fusion.
Given that the specific latent heat of fusion of ice is $336000 J . {kg}^{- 1}$ . It means that to melt 1 kg of ice at $0^{\circ} C$ to 1 kg of water at $0^{\circ} C$ , 336000 J of heat energy is needed.
The explanation for case(ii)
The amount of heat needed to raise the temperature of the unit mass of a substance by unity is known as the specific heat capacity.
Given that the specific heat capacity of copper is $0.4 J . g^{- 1} {}^{\circ}C^{- 1}$ . It means that 1 g of copper will absorb 0.4 J of heat energy to raise the temperature by $1^{\circ} C$ .

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Similar questions

State in brief, the meaning of each of the following:

The specific latent heat of fusion of ice is $3, 36, 000 J k g^{- 1}$ .

350 g of water at 30 degree C is contained in a copper vessel of mass 50 g. calculate the mass of ice required to bring down the temperature of the vessel and its contents to 5 degree C. given specific latent heat of fusion of ice=336000 J K^-1, specific heat capacity of copper=400 J K^-1, specific heat capacity of water=4200 J K^-1.

Q. A copper vessel of mass 100g contains 150g of water at

50^{o} C

. How much ice is needed to cool it to

5^{o} C

?
Given: Specific heat capacity of copper

= 0.4 J g^{- 1}

^{o} C^{- 1}

Specific heat capacity of water

= 4.2 J g^{- 1}

^{o} C^{- 1}

Specific latent heat of fusion of ice

= 336 J g^{- 1}

$250 g$ of water at $30 {}^{\circ}C$ is present in a copper vessel of mass $50 g$ . Calculate the mass of ice required to bring down the temperature of the vessel and its contents to $5 {}^{\circ}C$ .

(Specific latent heat of fusion of ice $= 336 \times 10^{3} J k g^{- 1}$

Specific heat capacity of copper vessel $= 400 J k g^{- 1} {}^{\circ}{C^{- 1}}$ ,

Specific heat capacity of water $= 4200 J k g^{- 1} {}^{\circ}{C^{- 1}}$ )

Q. How much heat energy is released when

5.0 g

water at

42^{\circ} C

changes into ice at

0^{\circ} C

? Take specific heat capacity of water =

4.2 J g^{- 1}

, specific latent heat of fusion of ice =

336 J g^{- 1}

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State in brief, the meaning of each of the following:(i) The specific latent heat of fusion of ice is 336000J.kg-1(ii) The specific heat capacity of copper is 0.4J.g-1C-1∘

State in brief, the meaning of each of the following:
(i) The specific latent heat of fusion of ice is $336000 J . {kg}^{- 1}$
(ii) The specific heat capacity of copper is $0.4 J . g^{- 1} {}^{\circ}C^{- 1}$