Question

State 'T' for true and 'F' for false.
i) If and y are non-zero rational numbers and m is a positive integer, then $x^m\times y^m=(xy{)}^{2m}$ and $x^m÷y^m={\left(\frac{x}{y}\right)}^1$
ii) Standard form of 38000000 is $3.8\times {10}^7$
iii) The base and power in $(-16\times 2{)}^4$ is -32 and 4 respectively.
iv) $6^2$ is greater than $2^6$

• A. T F F T
• B. F T T F
• C. F T F T
• D. T F T F

Answer 1

The correct option is B F T T F

$i)$ $x^m\times y^m=(x\cdot y{)}^m$ and $x^m÷y^m={\left(\frac{x}{y}\right)}^m$

$ii)$ $38000000$ can be written as $3.8\times {10}^7$

$iii)$ $(-16\times 2{)}^4$ in this base is $-16\times 2$ i.e., $32$ and power is $4$.

$iv)$ $2^6=64$ and $6^2=36$

So, $2^6>6^2$