Question

State 'T' for true and 'F' for false.
(i) It is possible to divide a line segment in 5 equal parts by perpendicularly bisecting a given line segment 5 times.
(ii) With a given centre and a given radius, only one circle can be drawn.
(iii) If we bisect an angle of a square, we get two angles of ${45}^o$ each.

• A. (i)-F (ii)-T (iii)-T
• B. (i)-F (ii)-T (iii)-F
• C. (i)-T (ii)-F (iii)-T
• D. (i)-T (ii)-T (iii)-F

Answer 1

The correct option is A (i)-F (ii)-T (iii)-T

$\left(i\right)$ It is possible to divide a line segment in $5$ equal parts by perpendicularly bisecting a given line segment $5$ times. $\left(False\right)$

$\left(ii\right)$ With a given centre and a given radius, only one circle can be drawn. $\left(True\right)$

$\left(iii\right)$ If we bisect an angle of a square, we get two angles of $45°$ each. $\left(True\right)$

In the each square, each angle is $90°.$ If we bisects we get $45°.$