You visited us 1 times! Enjoying our articles? Unlock Full Access!

Law of Mass Action

State the eff...

Question

State the effect of the following on the rection $2 S O_{2 (g)} + O_{2 (g)} ⇌ 2 S O_{3 (g)} + 189.4$ kJ at equilibrium:
(i) Temperature is increased.
(ii) Concentration of $S O_{2}$ is increased.
(iii) Pressure is decreased.
(iv) Helium is added at constant presuure.

Open in App

Solution

(i) Equilibrium will shift in backward direction which means backward reaction will be favoured.
(ii) Equilibrium will shift in forward direction or more of $S O_{3}$ will be formed.
(iii) Backward reaction will be favoured.
(iv) Backward reaction will be favoured.

Suggest Corrections

Similar questions

2 S O_{3} (g) ⇌ 2 S O_{2} (g)

S O_{2}

S O_{3}

S O_{2}

α

P_{2}

K_{p}

2 S O_{3} (g) ⇌ 2 S O_{2} (g) + O_{2} (g)

2 S O_{2} (g) + O_{2} (g) ⇌ 2 S O_{3} (g), Δ H = - X

2 S O_{2} (g) + O_{2} (g) ⇌ 2 S O_{3} (g)

[S O_{2}] = 0.60 M, [O_{2}] = 0.82 M

[S O_{3}] = 1.90 M

_{c}

2 S O_{2} (g) + O_{2} (g) ⇌ 2 {S O}_{3} (g) + X c a l

{S O}_{2}

Join BYJU'S Learning Program