State the electronic configuration for Boron [p=5, n=6].

2, 3

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5, 10

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5, 12

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5, 11

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Solution

The correct option is A 2, 3
As we know, atomic number is the total no of proton present in nucleus of an atom and atomic mass number is the total no of proton and neutron.
So boron have atomic number 5 and mass number $5 + 6 = 11$ . Therefore, K shell will accommodate 2 electrons and L shell will accommodate remaining electrons i.e 3. The electronic configuration is 2, 3.

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p = 2, n = 2

^{12} C_{5} + 7 .^{12} C_{6} + 21 .^{12} C_{7} + 35 .^{12} C_{8} + 35 .^{12} C_{9} + 21 .^{12} C_{10} + {7.}^{12} C_{11} +^{12} C_{12}

^{2 n + 1} C_{12}

n

n s^{2} n p^{5}

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