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Question

State the following statement is True or False
f(x)=2x321x2+36x30 is maximum at x=1.

A
True
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B
False
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Solution

The correct option is A True
f(x)=2x321x2+36x30
f(x)=d(f(x))dx=2×3x221×2x+36=6(x27x+6)
f′′(x)=6(2x7)
Equating f(x) to zero, we have x27x+6=0
(x1)(x6)=0 or x=1,6
f′′(1)=6(27)<0
f(x) has a maximum at x=1

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