Question

State the following statement is True or False

Distance from origin to the plane $6x-3y+2z+14=0$ is $2$.

• A. True
• B. False

Answer 1

The correct option is A True

Distance of a plane $ax+by+cz+d=0$ from origin is given by $\frac{|d|}{\sqrt{a^2+b^2+c^2}}$

Here, distance from origin $=\frac{14}{\sqrt{6^2+3^2+2^2}}$

$=\frac{14}{\sqrt{49}}$

$=\frac{14}{7}$

$=2$