The area (in sq. units) of the triangle formed by the points with polar coordinates (1,0)(2,π3) and (3,2π3), is 5√34
A
True
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B
False
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Solution
The correct option is A True Given points(1,0),(2,π3)and(3,2π3) Area of triangle, △=12|r1r2sin(θ2−θ1)+r2r3sin(θ3−θ2)+r3r1sin(θ1−θ3)| =12∣∣∣2sin(π3)+6sin(π3)+3sin(−2π3)∣∣∣ =12∣∣
∣∣8(√32)−3(√32)∣∣
∣∣ =5√34