State the following statement is True or False
The digit at ten's place of a two digit number exceeds the square of digit at units place ( $x$ ) by 5 and the number formed is $61$ , then the equation is $10 (x^{2} + 5) + x = 61$ .

True

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False

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Solution

The correct option is A True
Let the number at units place be $x$
then the number at ten's place = $x^{2} + 5$
Thus, the number so obtained is :
$10 (x^{2} + 5) + x = 61$

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Question 167

In a five-digit number, digit at ten's place is 4, digit at unit's place is one - fourth of ten's place digit, digit at hundred's place is 0, digit at thousand's place is 5 times of the digit at unit's place and ten thousand's place digit is double the digit at ten's place. Write the number.

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18

. If the digit at the unit's place is double the digit in the ten's place , what is the number ?

In a two – digit number, the digit in the unit's place exceeds twice the digit in the ten's place by 1. If the digit in the unit’s place and the ten’s place are interchanged, then the difference between the newly formed number and the original number is less than the original number by 1. What is the original number?

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State the following statement is True or FalseThe digit at ten's place of a two digit number exceeds the square of digit at units place (x) by 5 and the number formed is 61, then the equation is 10(x2+5)+x=61.

The correct option is A TrueLet the number at units place be xthen the number at ten's place = x2+5Thus, the number so obtained is :10(x2+5)+x=61

State the following statement is True or False
The digit at ten's place of a two digit number exceeds the square of digit at units place ( $x$ ) by 5 and the number formed is $61$ , then the equation is $10 (x^{2} + 5) + x = 61$ .

The correct option is A True
Let the number at units place be $x$
then the number at ten's place = $x^{2} + 5$
Thus, the number so obtained is :
$10 (x^{2} + 5) + x = 61$