Suppose AB is the chord. O is the centre of the circle. If
OM is the perpendicular drawn from O to AB as its distance, then OAM and OMB
are both right angled triangles.
Since, length of the chord is L, both AM and MB =L2
If r is the radius of the circle, then
=>OB2=OM2+MB2
=>r2=OM2+(L2)2
=>OM2=r2−L24
=>OM2=4r2−L24
=> Distance =OM=√4r2−L22