You visited us 1 times! Enjoying our articles? Unlock Full Access!

Mathematical Statements

State the nec...

Question

State the necessary condition for following statement to be true
'For any real number $x, (x^{2} - x)$ > 0.'

x

< 0,

x

> 1

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

x

> 0,

x

> 1

No worries! We‘ve got your back. Try BYJU‘S free classes today!

x

< 0,

x

No worries! We‘ve got your back. Try BYJU‘S free classes today!

x

= 0,

x

< 1

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Open in App

Solution

The correct option is A $x$ < 0, $x$ > 1
$(x^{2} - x)$ > 0
$x^{2}$ > $x$ or $x$ $(x - 1)$ > 0
for x < 0 LHS > 0 and
for x > 1 LHS > 0

Suggest Corrections

Similar questions

x > 0

\infty \int 0 e^{- t} | x - t | d t

a > 1

x, x^{2} \geq 0

f (x) = f_{1} (x) - 2 f_{2} (x)

f_{1} (x) = {\begin{matrix} min {x^{2}, | x |}, & | x | \leq 1 max {x^{2}, | x |}, & | x | > 1 \end{matrix}

f_{2} (x) = {\begin{matrix} min {x^{2}, | x |}, & | x | > 1 max {x^{2}, | x |}, & | x | \leq 1 \end{matrix}

g (x) = {\begin{matrix} min {f (t) : - 3 \leq t \leq x, - 3 \leq x < 0} max {f (t) : 0 \leq t \leq x, 0 \leq x \leq 3} \end{matrix}

x \in (- 1, 0)

f (x) + g (x)

3 x + 4 y + 7 = 0 and 5 x - 7 y - 2 = 0,

\frac{- 2}{7}

Join BYJU'S Learning Program