Question

State the number of images of an object placed between two mirrors, formed in each case when mirrors are inclined to each other at $\left(a\right){90}^{\circ }$ and $\left(b\right){60}^{\circ }$.

• A. $\left(a\right)4$, $\left(b\right)6$
• B. $\left(a\right)3$, $\left(b\right)5$
• C. $\left(a\right)2$, $\left(b\right)3$
• D. $\left(a\right)1$, $\left(b\right)2$

Answer 1

The correct option is B $\left(a\right)3$, $\left(b\right)5$

(a) When $\theta ={90}^0$,

$n=\frac{360}{90}-1=3$

(b) When $\theta ={60}^0$

$n=\frac{360}{60}-1=5$