State the number of terms in each of the expression:

$2 x + y + 8 \div y$

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Solution

Find the number of terms in $2 x + y + 8 \div y$

$2 x + y + 8 \div y = 2 x + y + \frac{8}{y}$ [Using BOMASS rule]
Here, $2 x + y + 8 \div y$ has three term unlike that are $2 x, y$ and $\frac{8}{y}$ which are separated by a plus sign.

Hence, the number of terms in $2 x + y + 8 \div y$ is $3$

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