Question

State the number of unpaired electrons in $N{i}^{2+}$:

• A. 0
• B. 2
• C. 4
• D. 8

Answer 1

The correct option is B 2

Electronic congiguration of $N{i}^{2+}$:$1s^{2}2s^{2}2p^{6}3s^{2}3p^{6}4s^{2}3d^8$
Unpaired electrons- 2

Hence option B is correct answer