State the order and degree of the given differential equation, if the order is a and degree is b, find a+b.
${[\frac{d^{2} x}{d t^{2}}]}^{3} + [\frac{d x}{d t}] - x t = 0$

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Solution

The correct option is B 5

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Similar questions

{[\frac{d^{2} x}{d t^{2}}]}^{3} + {[\frac{d x}{d t}]}^{4} - x t = 0

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\sqrt[3]{\frac{d y}{d x}} - 4 \frac{d^{2} y}{d x^{2}} - 7 x = 0

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