State the order of the following surds-i 101ii 53iii 294iv 74v 437

Surd an is said to be of the order #39;n #39;. (i) nbsp; nbsp; The order of nbsp; nbsp;101 is 2. (ii) nbsp; The order of nbsp; nbsp;53 is 3 ...

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Standard X

Mathematics

Class Interval

State the ord...

Question

State the order of the following surds.
(i) $\sqrt{101}$

(ii) $\sqrt[3]{5}$

(iii) $\sqrt[4]{29}$

(iv) $\sqrt[4]{7}$

(v) $\sqrt[7]{4^{3}}$

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Solution

Surd $\sqrt[n]{a}$ is said to be of the order 'n'.

(i) The order of $\sqrt{101}$ is 2.

(ii) The order of $\sqrt[3]{5}$ is 3.

(iii) The order of $\sqrt[4]{29}$ is 4.

(iv) The order of $\sqrt[4]{7}$ is 4.

(v) We can write $\sqrt[7]{4^{3}} as \sqrt[7]{64} .$

The order of $\sqrt[7]{64}$ is 7.

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Q. Write the order of the following surds:

(i)

\sqrt{50}

(ii)

\sqrt[3]{5}

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\sqrt{31^{\frac{1}{3}}}

(iv)

^{3} \sqrt{(9)^{2}}

(v)

\sqrt[4]{\frac{31}{50}}

Q. State the order of the surds given below.

(i) \sqrt[3]{7} (ii) 5 \sqrt{12} (iii) \sqrt[4]{10} (iv) \sqrt{39} (v) \sqrt[3]{18}

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(i)

\sqrt[4]{5}

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\sqrt[3]{6}

(iii)

\frac{4}{3} \sqrt{6}

(iv)

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(v)

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\sqrt{32}

(ii)

\sqrt{x^{3} y^{5}}

(iii)

2 \sqrt{2}

(iv)

\frac{3}{5} \sqrt{10}

(v) 3

\sqrt{72}

(vi) 2

\sqrt[3]{5}

(vii) 4

\sqrt[3]{3}

(viii)

\sqrt[4]{7}

(ix)

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\sqrt[5]{a^{2} b^{3} c^{4}}

Q. State which of the following are pure surds and mixed surds:

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\sqrt[5]{7}

(ii)

\sqrt{21}

(iii)

\sqrt[3]{34}

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\frac{3}{4} \sqrt{8}

(v)

\sqrt{1350}

(vi)

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(vii)

\sqrt[10]{3}

(viii)

\sqrt{9.3}

(ix)

\sqrt{0.4}

(x)

\sqrt{\frac{49}{10}}

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State the order of the following surds. (i) 101 (ii) 53 (iii) 294 (iv) 74 (v) 437

Surd an is said to be of the order 'n'. (i) The order of 101 is 2. (ii) The order of 53 is 3. (iii) The order of 294 is 4. (iv) The order of 74 is 4. (v) We can write 437as 647. The order of 647 is 7.

State the order of the following surds.
(i) $\sqrt{101}$

(ii) $\sqrt[3]{5}$

(iii) $\sqrt[4]{29}$

(iv) $\sqrt[4]{7}$

(v) $\sqrt[7]{4^{3}}$

Surd $\sqrt[n]{a}$ is said to be of the order 'n'.

(i) The order of $\sqrt{101}$ is 2.

(ii) The order of $\sqrt[3]{5}$ is 3.

(iii) The order of $\sqrt[4]{29}$ is 4.

(iv) The order of $\sqrt[4]{7}$ is 4.

(v) We can write $\sqrt[7]{4^{3}} as \sqrt[7]{64} .$

The order of $\sqrt[7]{64}$ is 7.